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PlayGround


    \frac{3}{4 \pi}   \sqrt{4 \cdot x^2   12}\\
    \lim_{n \to \infty}
    \sum_{k=1}^n \frac{1}{k^2} = \frac{\pi^2}{6}
    e^{i \pi} + 1 = 0 \\

playground/playground.1164205792.txt.gz · Last modified: 2019/06/27 15:59 (external edit)
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